What is the solution for (x(x+1)dy)/(dx)+xy=1,y(e)=1 ?

The solution for (x(x+1)dy)/(dx)+xy=1,y(e)=1 is y=(ln(x))/(x+1)+(c_{1})/(x+1)

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(x(x+1)dy)/(dx)+xy=1,y(e)=1

\frac{x ( x + 1 ) d y}{d x} + x y = 1, y (e) = 1

y = \frac{ln ( x )}{x + 1} + \frac{c _{1}}{x + 1}

Solution steps

\frac{x ( x + 1 ) d y}{d x} + x y = 1

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y = \frac{ln ( x )}{x + 1} + \frac{c _{1}}{x + 1}

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What is the solution for (x(x+1)dy)/(dx)+xy=1,y(e)=1 ?
The solution for (x(x+1)dy)/(dx)+xy=1,y(e)=1 is y=(ln(x))/(x+1)+(c_{1})/(x+1)