What is the derivative of y=(sqrt(4x-7)-sqrt(x))/5 ?

The derivative of y=(sqrt(4x-7)-sqrt(x))/5 is 1/5 (2/(sqrt(4x-7))-1/(2sqrt(x)))

What is the first derivative of y=(sqrt(4x-7)-sqrt(x))/5 ?

The first derivative of y=(sqrt(4x-7)-sqrt(x))/5 is 1/5 (2/(sqrt(4x-7))-1/(2sqrt(x)))

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derivative of

y = \frac{4 x - 7 - x}{5}

\frac{1}{5} (\frac{2}{4 x - 7} - \frac{1}{2 x})

Solution steps

\frac{d}{d x} (\frac{4 x - 7 - x}{5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{5} \frac{d}{d x} (4 x - 7 - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{5} (\frac{d}{d x} (4 x - 7) - \frac{d}{d x} (x))

\frac{d}{d x} (4 x - 7) = \frac{2}{4 x - 7}

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1}{5} (\frac{2}{4 x - 7} - \frac{1}{2 x})

\int (cos (x))^{2} d x

\int_{0}^{1} x (x - x) d x

\frac{d}{d x} (ln (x - 2))

\int_{0}^{π} (5 e^{x} + 5 sin (x)) d x

f (x) = \frac{1}{2 x}

What is the derivative of y=(sqrt(4x-7)-sqrt(x))/5 ?
The derivative of y=(sqrt(4x-7)-sqrt(x))/5 is 1/5 (2/(sqrt(4x-7))-1/(2sqrt(x)))
What is the first derivative of y=(sqrt(4x-7)-sqrt(x))/5 ?
The first derivative of y=(sqrt(4x-7)-sqrt(x))/5 is 1/5 (2/(sqrt(4x-7))-1/(2sqrt(x)))