What is the derivative of f(x)= 1/(2x) ?

The derivative of f(x)= 1/(2x) is -1/(2x^2)

What is the first derivative of f(x)= 1/(2x) ?

The first derivative of f(x)= 1/(2x) is -1/(2x^2)

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derivative of

f (x) = \frac{1}{2 x}

- \frac{1}{2 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{1}{2} (- 1 \cdot x^{- 1 - 1}) : - \frac{1}{2 x ^{2}}

= - \frac{1}{2 x ^{2}}

\int \frac{- x + 2}{x + 1} d x

\frac{\partial}{\partial x} (sin (x y^{2}))

f (x) = - x^{2} + 8 x - 8

- 3 e^{t}

\frac{x ^{2} - 2}{e ^{2 x}}

What is the derivative of f(x)= 1/(2x) ?
The derivative of f(x)= 1/(2x) is -1/(2x^2)
What is the first derivative of f(x)= 1/(2x) ?
The first derivative of f(x)= 1/(2x) is -1/(2x^2)