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Popular >

t^2y^'+ty=4,y(1)=6

Solution

t^{2} y^{^{'}} + t y = 4, y (1) = 6

Solution

y = \frac{4 ln ( t )}{t} + \frac{6}{t}

Solution steps

t^{2} y^{'} (t) + t y = 4

Solve linear ODE:

y = \frac{4 ln ( t )}{t} + \frac{6}{t}

y = \frac{4 ln ( t )}{t} + \frac{6}{t}

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Frequently Asked Questions (FAQ)

What is the solution for t^2y^'+ty=4,y(1)=6 ?
The solution for t^2y^'+ty=4,y(1)=6 is y=(4ln(t))/t+6/t