What is the limit as t approaches 0 of 2/t-2/(t^2+t) ?

The limit as t approaches 0 of 2/t-2/(t^2+t) is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as t approaches 0 of 2/t-2/(t^2+t)

t \to 0 lim (\frac{2}{t} - \frac{2}{t ^{2} + t})

2

Solution steps

t \to 0 lim (\frac{2}{t} - \frac{2}{t ^{2} + t})

Simplify

\frac{2}{t} - \frac{2}{t ^{2} + t} : \frac{2}{t + 1}

= t \to 0 lim (\frac{2}{t + 1})

Plug in the value

t = 0

= \frac{2}{0 + 1}

Simplify

= 2

5^{3 x}

(- 2, - 1), (4, 2)

\int e^{\frac{x}{100}} d x

\frac{d}{d x} (20 cos (4 x))

\int 3 sin (x) 1 + cos (x) d x

What is the limit as t approaches 0 of 2/t-2/(t^2+t) ?
The limit as t approaches 0 of 2/t-2/(t^2+t) is 2