What is the derivative of 20cos(4x) ?

The derivative of 20cos(4x) is -80sin(4x)

What is the first derivative of 20cos(4x) ?

The first derivative of 20cos(4x) is -80sin(4x)

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\frac{d}{d x} (20 cos (4 x))

- 80 sin (4 x)

Solution steps

\frac{d}{d x} (20 cos (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 20 \frac{d}{d x} (cos (4 x))

Apply the chain rule:

- sin (4 x) \frac{d}{d x} (4 x)

= - sin (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 20 (- sin (4 x) \cdot 4)

Simplify

= - 80 sin (4 x)

\int 3 sin (x) 1 + cos (x) d x

\frac{d}{d x} (3 + 2 x)

f (x) = \frac{x}{x - 2}, at x = 1

\int \frac{5 x ^{3} + 4 x}{x - 1} d x

\int \frac{x - 4}{x} d x

What is the derivative of 20cos(4x) ?
The derivative of 20cos(4x) is -80sin(4x)
What is the first derivative of 20cos(4x) ?
The first derivative of 20cos(4x) is -80sin(4x)