What is the first derivative of 3+2x ?

The first derivative of 3+2x is 2

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derivative of 3+2x

\frac{d}{d x} (3 + 2 x)

2

Solution steps

\frac{d}{d x} (3 + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) + \frac{d}{d x} (2 x)

\frac{d}{d x} (3) = 0

\frac{d}{d x} (2 x) = 2

= 0 + 2

Simplify

= 2

f (x) = \frac{x}{x - 2}, at x = 1

\int \frac{5 x ^{3} + 4 x}{x - 1} d x

\int \frac{x - 4}{x} d x

y^{^{'}} = \frac{7 x ^{6} e ^{\frac{y}{x}} + x ^{4} y ^{2}}{x ^{5} y}

(- 8, - 3), (- 3, 4)