What is the solution for y^'+5(cos(5x))y=-8cos(5x) ?

The solution for y^'+5(cos(5x))y=-8cos(5x) is y=(e^{-sin(5x)+c_{1}})/5-8/5

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y^'+5(cos(5x))y=-8cos(5x)

y^{^{'}} + 5 (cos (5 x)) y = - 8 cos (5 x)

y = \frac{e ^{- s i n (5 x) + c_{1}}}{5} - \frac{8}{5}

Solution steps

y^{'} (x) + 5 (cos (5 x)) y = - 8 cos (5 x)

Solve separable ODE:

y = \frac{e ^{- s i n (5 x) + c_{1}}}{5} - \frac{8}{5}

y = \frac{e ^{- s i n (5 x) + c_{1}}}{5} - \frac{8}{5}

y^{2} = 4 x, y^{2} = 8 x - 4, x

x \to 42 lim (\frac{x ^{2}}{6} - \frac{7}{x})

\frac{1 + 10 s}{s ^{2} + 10.1 s + 1}

\frac{\partial}{\partial x} ((x y - 5)^{2})

What is the solution for y^'+5(cos(5x))y=-8cos(5x) ?
The solution for y^'+5(cos(5x))y=-8cos(5x) is y=(e^{-sin(5x)+c_{1}})/5-8/5