What is the integral of 8/(sqrt(1-x^2)) ?

The integral of 8/(sqrt(1-x^2)) is 8arcsin(x)+C

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integral of 8/(sqrt(1-x^2))

\int \frac{8}{1 - x ^{2}} d x

8 arcsin (x) + C

Solution steps

\int \frac{8}{1 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int \frac{1}{1 - x ^{2}} d x

Use the common integral:

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= 8 arcsin (x)

Add a constant to the solution

= 8 arcsin (x) + C

\int \frac{x ^{2}}{121 + x ^{2}} d x

\int \frac{2 - e ^{x}}{e ^{9 x}} d x

\int_{0}^{\frac{π}{2}} sec^{4} (\frac{t}{2}) d t

x \to 3 lim (\frac{x - 3}{x ^{2} - 9})

What is the integral of 8/(sqrt(1-x^2)) ?
The integral of 8/(sqrt(1-x^2)) is 8arcsin(x)+C