What is (\partial)/(\partial y)(3x^2+y) ?

The answer to (\partial)/(\partial y)(3x^2+y) is 1

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(\partial)/(\partial y)(3x^2+y)

\frac{\partial}{\partial y} (3 x^{2} + y)

1

Solution steps

\frac{\partial}{\partial y} (3 x^{2} + y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2}) + \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (3 x^{2}) = 0

\frac{\partial}{\partial y} (y) = 1

= 0 + 1

Simplify

= 1

\int (sec^{3} (x)) d x

f (x) = x^{2} - 5 x + 5, (0, 5)

\frac{d}{d t} (e^{t} (cos (t)))

\frac{d}{d x} (x (ln (x) - 1))

\int_{0}^{\frac{3}{4}} \frac{1}{9 + 16 x ^{2}} d x

What is (\partial)/(\partial y)(3x^2+y) ?
The answer to (\partial)/(\partial y)(3x^2+y) is 1