What is the tangent of x^4-y^2=7,(2,3) ?

The tangent of x^4-y^2=7,(2,3) is y= 16/3 x-23/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of x^4-y^2=7,(2,3)

tangent of

x^{4} - y^{2} = 7, (2, 3)

y = \frac{16}{3} x - \frac{23}{3}

Solution steps

Find the slope of

x^{4} - y^{2} = 7 : \frac{d y}{d x} = \frac{2 x ^{3}}{y}

Compute the slope of

x^{4} - y^{2} = 7

(2, 3) : m = \frac{16}{3}

Find the line with slope m=

\frac{16}{3}

and passing through

(2, 3) : y = \frac{16}{3} x - \frac{23}{3}

y = \frac{16}{3} x - \frac{23}{3}

\int sec^{2} (θ) tan^{9} (θ) d θ

\frac{\partial}{\partial x} (2 sec^{2} (2 x - y))

2 x + y^{2} + 2 x y y^{^{'}} = 0

\frac{d}{d x} (x - ln (x + 1))

\int cos^{7} (9 - x) sin (9 - x) d x

What is the tangent of x^4-y^2=7,(2,3) ?
The tangent of x^4-y^2=7,(2,3) is y= 16/3 x-23/3