What is the derivative of x-ln(x+1) ?

The derivative of x-ln(x+1) is 1-1/(x+1)

What is the first derivative of x-ln(x+1) ?

The first derivative of x-ln(x+1) is 1-1/(x+1)

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\frac{d}{d x} (x - ln (x + 1))

1 - \frac{1}{x + 1}

Solution steps

\frac{d}{d x} (x - ln (x + 1))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (ln (x + 1))

\frac{d x}{d x} = 1

\frac{d}{d x} (ln (x + 1)) = \frac{1}{x + 1}

= 1 - \frac{1}{x + 1}

\int cos^{7} (9 - x) sin (9 - x) d x

v^{'} - 2 = 2 v^{2}

\frac{d}{d x} ((2 x + 7)^{3})

\frac{4}{s} (\frac{1}{6 + 5 s})

\int_{0}^{\frac{π}{2}} - 8 cos^{5} (x) d x

What is the derivative of x-ln(x+1) ?
The derivative of x-ln(x+1) is 1-1/(x+1)
What is the first derivative of x-ln(x+1) ?
The first derivative of x-ln(x+1) is 1-1/(x+1)