What is the limit as x approaches pi+of sec(x) ?

The limit as x approaches pi+of sec(x) is -1

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limit as x approaches pi+of sec(x)

x \to π + lim (sec (x))

- 1

Solution steps

x \to π + lim (sec (x))

Plug in the value

x = π

= sec (π)

Use the following trivial identity:

sec (π) = (- 1)

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

= - 1

\frac{\partial ^{3}}{\partial x \partial y \partial z} (e^{x y z^{5}})

\frac{2}{( ( s - 4 ) s ( s + 1 ) )}

\int x^{2} + 4 x - 8 d x

\int_{- 1}^{- 2} (\frac{16 - x ^{3}}{x ^{3}}) d x

f (x) = x - 7

What is the limit as x approaches pi+of sec(x) ?
The limit as x approaches pi+of sec(x) is -1