What is the derivative of ln(1-3x^2) ?

The derivative of ln(1-3x^2) is -(6x)/(1-3x^2)

What is the first derivative of ln(1-3x^2) ?

The first derivative of ln(1-3x^2) is -(6x)/(1-3x^2)

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\frac{d}{d x} (ln (1 - 3 x^{2}))

- \frac{6 x}{1 - 3 x ^{2}}

Solution steps

\frac{d}{d x} (ln (1 - 3 x^{2}))

Apply the chain rule:

\frac{1}{1 - 3 x ^{2}} \frac{d}{d x} (1 - 3 x^{2})

= \frac{1}{1 - 3 x ^{2}} \frac{d}{d x} (1 - 3 x^{2})

\frac{d}{d x} (1 - 3 x^{2}) = - 6 x

= \frac{1}{1 - 3 x ^{2}} (- 6 x)

Simplify

\frac{1}{1 - 3 x ^{2}} (- 6 x) : - \frac{6 x}{1 - 3 x ^{2}}

= - \frac{6 x}{1 - 3 x ^{2}}

\frac{d}{d x} (\frac{x ^{2} + 5 x + 6}{x ^{2} - 4})

\frac{\partial}{\partial y} (\frac{x ^{2}}{( x - y ) ^{2}})

\int - \frac{1}{x} d x

\frac{d}{d x} (ln (x^{13}))

\frac{d}{d x} (e^{(- 2 x)})

What is the derivative of ln(1-3x^2) ?
The derivative of ln(1-3x^2) is -(6x)/(1-3x^2)
What is the first derivative of ln(1-3x^2) ?
The first derivative of ln(1-3x^2) is -(6x)/(1-3x^2)