What is (\partial)/(\partial y)(-sin(y)) ?

The answer to (\partial)/(\partial y)(-sin(y)) is -cos(y)

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(\partial)/(\partial y)(-sin(y))

\frac{\partial}{\partial y} (- sin (y))

- cos (y)

Solution steps

\frac{\partial}{\partial y} (- sin (y))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial y} (sin (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= - cos (y)

\int (1 - \frac{x}{a})^{3} d x

y^{^{''}} + 20 y^{^{'}} + y = 12

x \to 0 lim (3 + x^{2} sin (\frac{1}{x}))

y = \frac{1}{x - 4}, x = 8

\frac{( x ^{2} + 2 x - 6 )}{( x + 1 ) ^{2}}

What is (\partial)/(\partial y)(-sin(y)) ?
The answer to (\partial)/(\partial y)(-sin(y)) is -cos(y)