What is the limit as x approaches 0 of 3+x^2sin(1/x) ?

The limit as x approaches 0 of 3+x^2sin(1/x) is 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of 3+x^2sin(1/x)

x \to 0 lim (3 + x^{2} sin (\frac{1}{x}))

3

Solution steps

x \to 0 lim (3 + x^{2} sin (\frac{1}{x}))

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 lim (3) + x \to 0 lim (x^{2} sin (\frac{1}{x}))

x \to 0 lim (3) = 3

x \to 0 lim (x^{2} sin (\frac{1}{x})) = 0

= 3 + 0

Simplify

= 3

y = \frac{1}{x - 4}, x = 8

\frac{( x ^{2} + 2 x - 6 )}{( x + 1 ) ^{2}}

((\frac{2}{s}) - (\frac{1}{s ^{3}}))^{2}

f (x) = \frac{x ^{2}}{x + 8}

\frac{d y}{d x} + (\frac{5}{x}) y = - 3 x - 4

What is the limit as x approaches 0 of 3+x^2sin(1/x) ?
The limit as x approaches 0 of 3+x^2sin(1/x) is 3