What is the solution for (dy)/(dx)+(5/x)y=-3x-4 ?

The solution for (dy)/(dx)+(5/x)y=-3x-4 is y=-(3x^2)/7-(2x)/3+(c_{1})/(x^5)

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(dy)/(dx)+(5/x)y=-3x-4

\frac{d y}{d x} + (\frac{5}{x}) y = - 3 x - 4

y = - \frac{3 x ^{2}}{7} - \frac{2 x}{3} + \frac{c _{1}}{x ^{5}}

Solution steps

\frac{d y}{d x} + (\frac{5}{x}) y = - 3 x - 4

Solve linear ODE:

y = - \frac{3 x ^{2}}{7} - \frac{2 x}{3} + \frac{c _{1}}{x ^{5}}

y = - \frac{3 x ^{2}}{7} - \frac{2 x}{3} + \frac{c _{1}}{x ^{5}}

y^{^{'}} + 5 y = 5 - e^{t}

3 x^{2} + 6

\int_{6}^{8} \frac{16}{( x - 6 ) ^{3}} d x

\frac{d}{d x} (x (2 x + 5)^{\frac{1}{3}})

f (x) = 2 x^{3} + 6 x^{2} - 49 x + 24

What is the solution for (dy)/(dx)+(5/x)y=-3x-4 ?
The solution for (dy)/(dx)+(5/x)y=-3x-4 is y=-(3x^2)/7-(2x)/3+(c_{1})/(x^5)