en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=2sqrt(x),y=2x

Solution

area

y = 2 x, y = 2 x

Solution

\frac{1}{3}

+1

Decimal Notation

0.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} 2 x - 2 x d x

Solve

\int_{0}^{1} 2 x - 2 x d x : \frac{1}{3}

The area is:

= \frac{1}{3}

Popular Examples

y^{''}-y^'-2y=e^x+x

y^{^{''}} - y^{^{'}} - 2 y = e^{x} + x

derivative of 1/9 ln(ln(x)+3)

\frac{d}{d x} (\frac{1}{9} ln (ln (x)) + 3)

x^{3} y^{^{'}} = y

tangent of f(x)=(2-4x^2)^5,\at x=1 tangent of

f (x) = (2 - 4 x^{2})^{5}, at x = 1

y^'+8(tan(8x))y=3cos(8x)

y^{^{'}} + 8 (tan (8 x)) y = 3 cos (8 x)

Frequently Asked Questions (FAQ)

What is area y=2sqrt(x),y=2x ?
The answer to area y=2sqrt(x),y=2x is 1/3