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Popular >

x^3y^'=y

Solution

x^{3} y^{^{'}} = y

Solution

y = e^{- \frac{1}{2 x ^{2}} + c_{1}}

Solution steps

x^{3} y^{'} (x) = y

Solve separable ODE:

y = e^{- \frac{1}{2 x ^{2}} + c_{1}}

y = e^{- \frac{1}{2 x ^{2}} + c_{1}}

Popular Examples

tangent of f(x)=(2-4x^2)^5,\at x=1 tangent of

f (x) = (2 - 4 x^{2})^{5}, at x = 1

y^'+8(tan(8x))y=3cos(8x)

y^{^{'}} + 8 (tan (8 x)) y = 3 cos (8 x)

derivative of f(x)=x^3-4x^2-6x+8 derivative of

f (x) = x^{3} - 4 x^{2} - 6 x + 8

integral of 1/x*ln(x)

\int \frac{1}{x} \cdot ln (x) d x

tangent of y=\sqrt[3]{x},(1,1)tangent of

Frequently Asked Questions (FAQ)

What is the solution for x^3y^'=y ?
The solution for x^3y^'=y is y=e^{-1/(2x^2)+c_{1}}