What is the derivative of e^{-3x}cos(2x) ?

The derivative of e^{-3x}cos(2x) is -3e^{-3x}cos(2x)-2e^{-3x}sin(2x)

What is the first derivative of e^{-3x}cos(2x) ?

The first derivative of e^{-3x}cos(2x) is -3e^{-3x}cos(2x)-2e^{-3x}sin(2x)

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\frac{d}{d x} (e^{- 3 x} cos (2 x))

- 3 e^{- 3 x} cos (2 x) - 2 e^{- 3 x} sin (2 x)

Solution steps

\frac{d}{d x} (e^{- 3 x} cos (2 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{- 3 x}, g = cos (2 x)

= \frac{d}{d x} (e^{- 3 x}) cos (2 x) + \frac{d}{d x} (cos (2 x)) e^{- 3 x}

\frac{d}{d x} (e^{- 3 x}) = - 3 e^{- 3 x}

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= (- 3 e^{- 3 x}) cos (2 x) + (- sin (2 x) \cdot 2) e^{- 3 x}

Simplify

= - 3 e^{- 3 x} cos (2 x) - 2 e^{- 3 x} sin (2 x)

\int \frac{9}{25 + 16 r ^{2}} d r

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\frac{d}{d x} ([x + (x + sin^{2} (x))^{7}]^{5})

\frac{d y}{d x} + \frac{1}{x} y = 10 x^{2}

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What is the derivative of e^{-3x}cos(2x) ?
The derivative of e^{-3x}cos(2x) is -3e^{-3x}cos(2x)-2e^{-3x}sin(2x)
What is the first derivative of e^{-3x}cos(2x) ?
The first derivative of e^{-3x}cos(2x) is -3e^{-3x}cos(2x)-2e^{-3x}sin(2x)