What is the derivative of 3x^2-3/(x^4) ?

The derivative of 3x^2-3/(x^4) is 6x+(12)/(x^5)

What is the first derivative of 3x^2-3/(x^4) ?

The first derivative of 3x^2-3/(x^4) is 6x+(12)/(x^5)

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\frac{d}{d x} (3 x^{2} - \frac{3}{x ^{4}})

6 x + \frac{12}{x ^{5}}

Solution steps

\frac{d}{d x} (3 x^{2} - \frac{3}{x ^{4}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (\frac{3}{x ^{4}})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (\frac{3}{x ^{4}}) = - \frac{12}{x ^{5}}

= 6 x - (- \frac{12}{x ^{5}})

Simplify

= 6 x + \frac{12}{x ^{5}}

\frac{d}{d x} (arctan ((x + y)^{2}))

x \to - 1 - lim (5 x + 2 p (x))

f (x) = \frac{5 ^{x}}{cos ( x )}

f (x) = (x - 3) (2 x + 1)

\frac{1}{2} \frac{d y}{d x} = y + 2

What is the derivative of 3x^2-3/(x^4) ?
The derivative of 3x^2-3/(x^4) is 6x+(12)/(x^5)
What is the first derivative of 3x^2-3/(x^4) ?
The first derivative of 3x^2-3/(x^4) is 6x+(12)/(x^5)