What is the solution for derivative of y=x^3(2-x^2) ?

The solution for derivative of y=x^3(2-x^2) is y= 1/4 x^4(2-x^2)+(x^6)/(12)+c_{1}

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derivative of y=x^3(2-x^2)

\frac{d}{d x} y = x^{3} (2 - x^{2})

y = \frac{1}{4} x^{4} (2 - x^{2}) + \frac{x ^{6}}{12} + c_{1}

Solution steps

\frac{d y}{d x} = x^{3} (2 - x^{2})

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x^{3} (2 - x^{2}) d x

\int x^{3} (2 - x^{2}) d x = \frac{1}{4} x^{4} (2 - x^{2}) + \frac{x ^{6}}{12} + c_{1}

y = \frac{1}{4} x^{4} (2 - x^{2}) + \frac{x ^{6}}{12} + c_{1}

y = x^{0.95}

a^{4} + cos^{4} (x)

\int_{0}^{1} y d y

x \to 0 lim (\frac{- 6}{x ^{2}})

What is the solution for derivative of y=x^3(2-x^2) ?
The solution for derivative of y=x^3(2-x^2) is y= 1/4 x^4(2-x^2)+(x^6)/(12)+c_{1}