What is (\partial)/(\partial x)(-3x^2y^2) ?

The answer to (\partial)/(\partial x)(-3x^2y^2) is -6xy^2

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(\partial)/(\partial x)(-3x^2y^2)

\frac{\partial}{\partial x} (- 3 x^{2} y^{2})

- 6 x y^{2}

Solution steps

\frac{\partial}{\partial x} (- 3 x^{2} y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 y^{2} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 3 y^{2} \cdot 2 x^{2 - 1}

Simplify

= - 6 x y^{2}

y = x^{2} + 4, (- 2, 8)

f (x) = 3 x^{\frac{2}{3}} - 2 x

x \to 0 - lim (- \frac{1}{x})

n = 1 \sum \infty \frac{5 n}{6 n + 5}

y = arccot (7 t)

What is (\partial)/(\partial x)(-3x^2y^2) ?
The answer to (\partial)/(\partial x)(-3x^2y^2) is -6xy^2