What is the first derivative of-2x+9 ?

The first derivative of-2x+9 is -2

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derivative of-2x+9

\frac{d}{d x} (- 2 x + 9)

- 2

Solution steps

\frac{d}{d x} (- 2 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x) + \frac{d}{d x} (9)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (9) = 0

= - 2 + 0

Simplify

= - 2

\frac{x}{( x ^{2} - 4 )}

3 x^{2} + 2 x, at x = - 1

y = \frac{π x}{12}

\frac{d}{d x} (2 e^{- x} cos (x))

f (x) = \frac{2 x ^{2} + 2 x + 4}{x}