What is the integral from 0 to 2 of 6x^2 ?

The integral from 0 to 2 of 6x^2 is 16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of 6x^2

\int_{0}^{2} 6 x^{2} d x

16

Solution steps

\int_{0}^{2} 6 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{0}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{2}

= 6 [\frac{x ^{3}}{3}]_{0}^{2}

Compute the boundaries:

\frac{8}{3}

= 6 \cdot \frac{8}{3}

Simplify

= 16

\int_{- 1}^{1} x 1 - x^{2} d x

\int sin (24 x) cos (15 x) d x

\frac{d}{d x} (\frac{8}{x - 2})

\int x^{2} \cdot e^{x^{3} + 4} d x

\frac{d}{d x} (r (θ, x) cos (θ))

What is the integral from 0 to 2 of 6x^2 ?
The integral from 0 to 2 of 6x^2 is 16