What is (\partial)/(\partial y)(x^2y-xy^2) ?

The answer to (\partial)/(\partial y)(x^2y-xy^2) is x^2-2xy

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(\partial)/(\partial y)(x^2y-xy^2)

\frac{\partial}{\partial y} (x^{2} y - x y^{2})

x^{2} - 2 x y

Solution steps

\frac{\partial}{\partial y} (x^{2} y - x y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2} y) - \frac{\partial}{\partial y} (x y^{2})

\frac{\partial}{\partial y} (x^{2} y) = x^{2}

\frac{\partial}{\partial y} (x y^{2}) = 2 x y

= x^{2} - 2 x y

y = \frac{tan ( x ) - 1}{sec ( x )}

y^{^{'''}} - 9 y^{^{''}} + y^{^{'}} - 9 y = 0

y^{^{''}} - 4 y^{^{'}} + 3 y = (2 x + 1) e^{- x}

x \to 0 - lim (\frac{0}{x ^{2} ∣ x ∣})

\frac{d}{d x} (\frac{e ^{x}}{3})

What is (\partial)/(\partial y)(x^2y-xy^2) ?
The answer to (\partial)/(\partial y)(x^2y-xy^2) is x^2-2xy