What is (\partial)/(\partial y)((cy)/(x^2+y^2)) ?

The answer to (\partial)/(\partial y)((cy)/(x^2+y^2)) is (c(x^2-y^2))/((x^2+y^2)^2)

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(\partial)/(\partial y)((cy)/(x^2+y^2))

\frac{\partial}{\partial y} (\frac{cy}{x ^{2} + y ^{2}})

\frac{c ( x ^{2} - y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial y} (\frac{cy}{x ^{2} + y ^{2}})

Treat

c, x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= c \frac{\partial}{\partial y} (\frac{y}{x ^{2} + y ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= c \frac{\frac{\partial}{\partial y} ( y ) ( x ^{2} + y ^{2} ) - \frac{\partial}{\partial y} ( x ^{2} + y ^{2} ) y}{( x ^{2} + y ^{2} ) ^{2}}

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (x^{2} + y^{2}) = 2 y

= c \frac{1 \cdot ( x ^{2} + y ^{2} ) - 2 yy}{( x ^{2} + y ^{2} ) ^{2}}

Simplify

c \frac{1 \cdot ( x ^{2} + y ^{2} ) - 2 yy}{( x ^{2} + y ^{2} ) ^{2}} : \frac{c ( x ^{2} - y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

= \frac{c ( x ^{2} - y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

(4 + x) y^{^{'}} = y^{3}

x \to 2 lim (\frac{1}{x - 1})

i = 1 \sum \infty (i) \cdot \frac{1}{6 ^{i}}

x \to 2 lim (\frac{x + 2}{x})

\frac{\partial}{\partial y} (x y d x)

What is (\partial)/(\partial y)((cy)/(x^2+y^2)) ?
The answer to (\partial)/(\partial y)((cy)/(x^2+y^2)) is (c(x^2-y^2))/((x^2+y^2)^2)