What is the derivative of y=3x^2+17x+10 ?

The derivative of y=3x^2+17x+10 is 6x+17

What is the first derivative of y=3x^2+17x+10 ?

The first derivative of y=3x^2+17x+10 is 6x+17

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derivative of

y = 3 x^{2} + 17 x + 10

6 x + 17

Solution steps

\frac{d}{d x} (3 x^{2} + 17 x + 10)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (17 x) + \frac{d}{d x} (10)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (17 x) = 17

\frac{d}{d x} (10) = 0

= 6 x + 17 + 0

Simplify

= 6 x + 17

\frac{\partial}{\partial x} (x^{2} y + x + y)

2 y^{^{''}} - 2 y^{^{'}} + 5 y = 0

\frac{d}{d x} (\frac{e ^{x}}{3 + e ^{x}})

\frac{d}{d x} (7 sin (x) - 2 x^{3})

\int \frac{x ^{2} + 36 x + 36}{x ^{3} - 4 x} d x

What is the derivative of y=3x^2+17x+10 ?
The derivative of y=3x^2+17x+10 is 6x+17
What is the first derivative of y=3x^2+17x+10 ?
The first derivative of y=3x^2+17x+10 is 6x+17