What is the d/(d{x)}({x}^2+{y}{z}) ?

The d/(d{x)}({x}^2+{y}{z}) is 2{x}

What is the first d/(d{x)}({x}^2+{y}{z}) ?

The first d/(d{x)}({x}^2+{y}{z}) is 2{x}

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\frac{d}{d x} (x^{2} + y z)

2 x

Solution steps

\frac{d}{d x} (x^{2} + y z)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (y z)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (y z) = 0

= 2 x + 0

Simplify

= 2 x

y = 8 x^{2} - x^{3} (2.24)

n = 0 \sum \infty \frac{( 8 ^{n} )}{n !}

y^{^{'}} + y = y^{2}

\frac{d}{d x} (30 x^{4} y^{7} - 24 x^{12} y^{3})

\int 9 x e^{15 x} d x

What is the d/(d{x)}({x}^2+{y}{z}) ?
The d/(d{x)}({x}^2+{y}{z}) is 2{x}
What is the first d/(d{x)}({x}^2+{y}{z}) ?
The first d/(d{x)}({x}^2+{y}{z}) is 2{x}