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Popular >

y^'+y=y^2

Solution

y^{^{'}} + y = y^{2}

Solution

y = \frac{1}{1 - e ^{t + c_{1}}}

Solution steps

y^{'} (t) + y = y^{2}

Solve separable ODE:

y = \frac{1}{1 - e ^{t + c_{1}}}

y = \frac{1}{1 - e ^{t + c_{1}}}

Popular Examples

derivative of 30x^4y^7-24x^{12}y^3

\frac{d}{d x} (30 x^{4} y^{7} - 24 x^{12} y^{3})

integral of 9xe^{15x}

\int 9 x e^{15 x} d x

derivative of-e^{x^2}

\frac{d}{d x} (- e^{x^{2}})

tangent of f(x)=sqrt(7x),(7,7)tangent of

f (x) = 7 x, (7, 7)

6 e^{2 x - y} d x = d y

Frequently Asked Questions (FAQ)

What is the solution for y^'+y=y^2 ?
The solution for y^'+y=y^2 is y= 1/(1-e^{t+c_{1)}}