What is the tangent of f(x)=sqrt(7x),(7,7) ?

The tangent of f(x)=sqrt(7x),(7,7) is y= 1/2 x+7/2

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tangent of f(x)=sqrt(7x),(7,7)

tangent of

f (x) = 7 x, (7, 7)

y = \frac{1}{2} x + \frac{7}{2}

Solution steps

Find the slope of

f (x) = 7 x : \frac{df ( x )}{d x} = \frac{7}{2 x}

Compute the slope of

f (x) = 7 x

(7, 7) : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(7, 7) : y = \frac{1}{2} x + \frac{7}{2}

y = \frac{1}{2} x + \frac{7}{2}

6 e^{2 x - y} d x = d y

\int \frac{1}{x ( x - a )} d x

\frac{\partial}{\partial y} (x + ln (y))

\int_{1}^{e^{5}} x^{4} ln (x) d x

y = \frac{x ^{2} - 1}{x ^{2} + 1}

What is the tangent of f(x)=sqrt(7x),(7,7) ?
The tangent of f(x)=sqrt(7x),(7,7) is y= 1/2 x+7/2