What is (\partial)/(\partial y)(x+ln(y)) ?

The answer to (\partial)/(\partial y)(x+ln(y)) is 1/y

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(\partial)/(\partial y)(x+ln(y))

\frac{\partial}{\partial y} (x + ln (y))

\frac{1}{y}

Solution steps

\frac{\partial}{\partial y} (x + ln (y))

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (ln (y))

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (ln (y)) = \frac{1}{y}

= 0 + \frac{1}{y}

Simplify

= \frac{1}{y}

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What is (\partial)/(\partial y)(x+ln(y)) ?
The answer to (\partial)/(\partial y)(x+ln(y)) is 1/y