What is the slope of y=x^3,\at x=5 ?

The slope of y=x^3,\at x=5 is 75

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slope of y=x^3,\at x=5

slope

y = x^{3}, at x = 5

75

Solution steps

y = x^{3}

In order to find the slope of the function, take the derivative of

x^{3}

\frac{d}{d x} (x^{3}) = 3 x^{2}

3 x^{2}

Find the value of

3 x^{2}

for

x = 5 : 75

75

\frac{2 r - 1}{t} d r + \frac{r - 2 r ^{2}}{t ^{2} - 1} d t = 0

\frac{d}{d x} (3 x^{4} - 2 x^{3} - 12 x^{2} + 18 x + 15)

g (x) = x + x

2 sin (x), 3 cos (x)

\frac{d}{d x} (\frac{1}{ln ( x ^{2} )})