What is the derivative of g(x)=x+sqrt(x) ?

The derivative of g(x)=x+sqrt(x) is 1+1/(2sqrt(x))

What is the first derivative of g(x)=x+sqrt(x) ?

The first derivative of g(x)=x+sqrt(x) is 1+1/(2sqrt(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

g (x) = x + x

1 + \frac{1}{2 x}

Solution steps

\frac{d}{d x} (x + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (x)

\frac{d x}{d x} = 1

\frac{d}{d x} (x) = \frac{1}{2 x}

= 1 + \frac{1}{2 x}

2 sin (x), 3 cos (x)

\frac{d}{d x} (\frac{1}{ln ( x ^{2} )})

\frac{\partial}{\partial y} (x^{2} - y^{2})

\frac{\partial}{\partial θ} (ρ sin (φ) cos (θ))

\frac{\partial}{\partial y} (ln (x^{2} y^{2}))

What is the derivative of g(x)=x+sqrt(x) ?
The derivative of g(x)=x+sqrt(x) is 1+1/(2sqrt(x))
What is the first derivative of g(x)=x+sqrt(x) ?
The first derivative of g(x)=x+sqrt(x) is 1+1/(2sqrt(x))