What is the derivative of (x+1)^2 ?

The derivative of (x+1)^2 is 2(x+1)

What is the first derivative of (x+1)^2 ?

The first derivative of (x+1)^2 is 2(x+1)

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derivative of

(x + 1)^{2}

2 (x + 1)

Solution steps

\frac{d}{d x} ((x + 1)^{2})

Apply the chain rule:

2 (x + 1) \frac{d}{d x} (x + 1)

= 2 (x + 1) \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 2 (x + 1) \cdot 1

Simplify

= 2 (x + 1)

\frac{d y}{d x} = \frac{x ^{3} + 2 y ^{3}}{x y ^{2}}

e^{- π s} \frac{2}{s ^{3}}

2 x csc (x) - x^{2} cot (x) csc (x)

\int_{3}^{\infty} e^{- \frac{x}{4}} d x

\frac{\partial}{\partial x} (9 cos (y e^{x y}) sin (x))

What is the derivative of (x+1)^2 ?
The derivative of (x+1)^2 is 2(x+1)
What is the first derivative of (x+1)^2 ?
The first derivative of (x+1)^2 is 2(x+1)