What is the derivative of x^3-2x+3x^{-3} ?

The derivative of x^3-2x+3x^{-3} is 3x^2-2-9/(x^4)

What is the first derivative of x^3-2x+3x^{-3} ?

The first derivative of x^3-2x+3x^{-3} is 3x^2-2-9/(x^4)

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\frac{d}{d x} (x^{3} - 2 x + 3 x^{- 3})

3 x^{2} - 2 - \frac{9}{x ^{4}}

Solution steps

\frac{d}{d x} (x^{3} - 2 x + 3 x^{- 3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (3 x^{- 3})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3 x^{- 3}) = - \frac{9}{x ^{4}}

= 3 x^{2} - 2 - \frac{9}{x ^{4}}

y = ln (lo g_{e} (3 x))

- 4

\int_{1}^{\infty} 0 d x

\int sec (x) tan^{4} (x) d x

\int x^{2} - 6 x d x

What is the derivative of x^3-2x+3x^{-3} ?
The derivative of x^3-2x+3x^{-3} is 3x^2-2-9/(x^4)
What is the first derivative of x^3-2x+3x^{-3} ?
The first derivative of x^3-2x+3x^{-3} is 3x^2-2-9/(x^4)