What is the integral of x^2-6sqrt(x) ?

The integral of x^2-6sqrt(x) is (x^3)/3-4x^{3/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x^2-6sqrt(x)

\int x^{2} - 6 x d x

\frac{x ^{3}}{3} - 4 x^{\frac{3}{2}} + C

Solution steps

\int x^{2} - 6 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 6 x d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 6 x d x = 4 x^{\frac{3}{2}}

= \frac{x ^{3}}{3} - 4 x^{\frac{3}{2}}

Add a constant to the solution

= \frac{x ^{3}}{3} - 4 x^{\frac{3}{2}} + C

\int 1^{x} d x

\int 7 e^{c o s (x)} sin (x) d x

cos (2 t) - 5 t

x \to 3 lim (5 x^{3} - 2 x^{2} + x - 9)

\int \frac{tan ( \frac{2}{t} )}{t ^{2}} d t

What is the integral of x^2-6sqrt(x) ?
The integral of x^2-6sqrt(x) is (x^3)/3-4x^{3/2}+C