What is laplacetransform cos(2t)-5t ?

The answer to laplacetransform cos(2t)-5t is s/(s^2+4)-5/(s^2)

Popular >

laplacetransform cos(2t)-5t

laplace transform

cos (2 t) - 5 t

\frac{s}{s ^{2} + 4} - \frac{5}{s ^{2}}

Solution steps

L {cos (2 t) - 5 t}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {cos (2 t)} - 5 L {t}

L {cos (2 t)} : \frac{s}{s ^{2} + 4}

L {t} : \frac{1}{s ^{2}}

= \frac{s}{s ^{2} + 4} - 5 \cdot \frac{1}{s ^{2}}

Refine

\frac{s}{s ^{2} + 4} - 5 \frac{1}{s ^{2}} : \frac{s}{s ^{2} + 4} - \frac{5}{s ^{2}}

= \frac{s}{s ^{2} + 4} - \frac{5}{s ^{2}}

x \to 3 lim (5 x^{3} - 2 x^{2} + x - 9)

\int \frac{tan ( \frac{2}{t} )}{t ^{2}} d t

\frac{4}{s - 3}

\int_{3}^{5} x x^{2} - 9 d x

x \to \infty lim (h (x))

What is laplacetransform cos(2t)-5t ?
The answer to laplacetransform cos(2t)-5t is s/(s^2+4)-5/(s^2)