What is the derivative of x^3-6x^2+9x+1 ?

The derivative of x^3-6x^2+9x+1 is 3x^2-12x+9

What is the first derivative of x^3-6x^2+9x+1 ?

The first derivative of x^3-6x^2+9x+1 is 3x^2-12x+9

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\frac{d}{d x} (x^{3} - 6 x^{2} + 9 x + 1)

3 x^{2} - 12 x + 9

Solution steps

\frac{d}{d x} (x^{3} - 6 x^{2} + 9 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (9 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (1) = 0

= 3 x^{2} - 12 x + 9 + 0

Simplify

= 3 x^{2} - 12 x + 9

\frac{d}{d x} (2 x + x^{2})

\int tan^{2} (8 x) d x

y = \frac{e ^{x}}{x - 1}

\frac{d y}{d x} = \frac{( e ^{- y} + e ^{- 5 x - y} )}{e ^{x} y}

x \to 1 lim (- 9 + 3 x^{2})

What is the derivative of x^3-6x^2+9x+1 ?
The derivative of x^3-6x^2+9x+1 is 3x^2-12x+9
What is the first derivative of x^3-6x^2+9x+1 ?
The first derivative of x^3-6x^2+9x+1 is 3x^2-12x+9