What is (\partial)/(\partial x)(1/3 x^3y^3) ?

The answer to (\partial)/(\partial x)(1/3 x^3y^3) is x^2y^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(1/3 x^3y^3)

\frac{\partial}{\partial x} (\frac{1}{3} x^{3} y^{3})

x^{2} y^{3}

Solution steps

\frac{\partial}{\partial x} (\frac{1}{3} x^{3} y^{3})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} y^{3} \frac{\partial}{\partial x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{3} y^{3} \cdot 3 x^{3 - 1}

Simplify

\frac{1}{3} y^{3} \cdot 3 x^{3 - 1} : x^{2} y^{3}

= x^{2} y^{3}

\int_{8}^{9} x x - 8 d x

((x - x^{2}) - (x^{2} - 6 x)), 0, 3.5

f (x) = 2 sin (x) + 6 cos (x), at x = 0

\frac{\partial}{\partial x} (x^{8} y^{4} - x^{7} y^{3})

\frac{d}{d x} (5 (2 x e^{x} + e^{x} x^{2}))

What is (\partial)/(\partial x)(1/3 x^3y^3) ?
The answer to (\partial)/(\partial x)(1/3 x^3y^3) is x^2y^3