What is the tangent of f(x)=2sin(x)+6cos(x),\at x=0 ?

The tangent of f(x)=2sin(x)+6cos(x),\at x=0 is y=2x+6

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tangent of f(x)=2sin(x)+6cos(x),\at x=0

tangent of

f (x) = 2 sin (x) + 6 cos (x), at x = 0

y = 2 x + 6

Solution steps

Find the tangent point:

(0, 6)

Find the slope of

f (x) = 2 sin (x) + 6 cos (x) : \frac{df ( x )}{d x} = 2 cos (x) - 6 sin (x)

Compute the slope of

f (x) = 2 sin (x) + 6 cos (x)

x = 0 : m = 2

Find the line with slope m=

2

and passing through

(0, 6) : y = 2 x + 6

y = 2 x + 6

\frac{\partial}{\partial x} (x^{8} y^{4} - x^{7} y^{3})

\frac{d}{d x} (5 (2 x e^{x} + e^{x} x^{2}))

\int_{1}^{4} 10 t ln (t) d t

\frac{\partial}{\partial x} (6 y^{2} + 478 x - 10)

\frac{d}{d x} (- \frac{2 x}{( 4 + x ^{2} ) ^{2}})

What is the tangent of f(x)=2sin(x)+6cos(x),\at x=0 ?
The tangent of f(x)=2sin(x)+6cos(x),\at x=0 is y=2x+6