What is area y= 1/2 x^3+2,y=x+1,0,2 ?

The answer to area y= 1/2 x^3+2,y=x+1,0,2 is 2

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area y= 1/2 x^3+2,y=x+1,0,2

area

y = \frac{1}{2} x^{3} + 2, y = x + 1, 0, 2

2

Solution steps

Apply the area formula:

\int_{0}^{2} \frac{1}{2} x^{3} + 2 - (x + 1) d x

Solve

\int_{0}^{2} \frac{1}{2} x^{3} + 2 - (x + 1) d x : 2

The area is:

= 2

f (x) = x^{2} + x, (- 2, 2)

\int_{3}^{7} \frac{1}{6 x + 7} d x

\frac{\partial}{\partial u} (\frac{v}{u - v})

\frac{d y}{d x} = 2 sin (x) (y - 3)

\frac{d}{d x} (\frac{3}{2 3 x + 1})

What is area y= 1/2 x^3+2,y=x+1,0,2 ?
The answer to area y= 1/2 x^3+2,y=x+1,0,2 is 2