What is the tangent of f(x)=x^2+x,(-2,2) ?

The tangent of f(x)=x^2+x,(-2,2) is y=-3x-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2+x,(-2,2)

tangent of

f (x) = x^{2} + x, (- 2, 2)

y = - 3 x - 4

Solution steps

Find the slope of

f (x) = x^{2} + x : \frac{df ( x )}{d x} = 2 x + 1

Compute the slope of

f (x) = x^{2} + x

(- 2, 2) : m = - 3

Find the line with slope m=

- 3

and passing through

(- 2, 2) : y = - 3 x - 4

y = - 3 x - 4

\int_{3}^{7} \frac{1}{6 x + 7} d x

\frac{\partial}{\partial u} (\frac{v}{u - v})

\frac{d y}{d x} = 2 sin (x) (y - 3)

\frac{d}{d x} (\frac{3}{2 3 x + 1})

x \to 0 lim (4 cos (2 x))

What is the tangent of f(x)=x^2+x,(-2,2) ?
The tangent of f(x)=x^2+x,(-2,2) is y=-3x-4