What is laplacetransform e^{-2t}t^2 ?

The answer to laplacetransform e^{-2t}t^2 is 2/((s+2)^3)

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laplacetransform e^{-2t}t^2

laplace transform

e^{- 2 t} t^{2}

\frac{2}{( s + 2 ) ^{3}}

Solution steps

L {e^{- 2 t} t^{2}}

Use Laplace Transform table:

L {t^{k} f (t)} = (- 1)^{k} \frac{d ^{k}}{d s ^{k}} (L {f (t)})

For

e^{- 2 t} t^{2} : f (t) = e^{- 2 t}, k = 2

= (- 1)^{2} \frac{d ^{2}}{d s ^{2}} (L {e^{- 2 t}})

L {e^{- 2 t}} : \frac{1}{s + 2}

\frac{d ^{2}}{d s ^{2}} (\frac{1}{s + 2}) = \frac{2}{( s + 2 ) ^{3}}

= (- 1)^{2} \frac{2}{( s + 2 ) ^{3}}

= \frac{2}{( s + 2 ) ^{3}}

x \to 0 lim (x^{6} e^{- x^{5}})

\int_{1}^{\infty} x^{2} ln (x) d x

(12 y^{2} - x \cdot y) d x + (x^{2}) d y = 0

\int (- 3 x + 4) \cdot e^{- x} d x

\frac{d}{d x} (\frac{3 x ^{2}}{1 + x ^{3}})

What is laplacetransform e^{-2t}t^2 ?
The answer to laplacetransform e^{-2t}t^2 is 2/((s+2)^3)