What is the first derivative of 3x+9 ?

The first derivative of 3x+9 is 3

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derivative of 3x+9

\frac{d}{d x} (3 x + 9)

3

Solution steps

\frac{d}{d x} (3 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (9)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (9) = 0

= 3 + 0

Simplify

= 3

\frac{\partial}{\partial y} (e^{a x + y} + e^{y})

a^{(\frac{1}{2})} (7 x - a) + 2 a

x - x^{3}

x^{\frac{1}{3} + y^{\frac{1}{3}}} = 7

y^{^{''}} - 2 y^{^{'}} + 17 y = 0