What is the derivative of 2x^2+5x+18 ?

The derivative of 2x^2+5x+18 is 4x+5

What is the first derivative of 2x^2+5x+18 ?

The first derivative of 2x^2+5x+18 is 4x+5

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\frac{d}{d x} (2 x^{2} + 5 x + 18)

4 x + 5

Solution steps

\frac{d}{d x} (2 x^{2} + 5 x + 18)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (5 x) + \frac{d}{d x} (18)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (18) = 0

= 4 x + 5 + 0

Simplify

= 4 x + 5

t \to 0 lim (\frac{8 ^{t} - 5 ^{t}}{t})

\int \frac{y ^{2}}{y + 1} d y

\frac{\partial}{\partial u} (v sin (u))

\frac{d}{d x} (2 sec (x))

\frac{d}{d x} (\frac{3 - 8 x}{x + 4})

What is the derivative of 2x^2+5x+18 ?
The derivative of 2x^2+5x+18 is 4x+5
What is the first derivative of 2x^2+5x+18 ?
The first derivative of 2x^2+5x+18 is 4x+5