What is the sum from k=0 to infinity of (3^k)/(k!) ?

The sum from k=0 to infinity of (3^k)/(k!) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from k=0 to infinity of (3^k)/(k!)

k = 0 \sum \infty \frac{3 ^{k}}{k !}

converges

Solution steps

k = 0 \sum \infty \frac{3 ^{k}}{k !}

Apply Series Ratio Test:

converges

= converges

\frac{x ^{2} - 3 x + 11}{x ^{2} + x - 3}

\frac{\partial}{\partial θ} (cos (θ))

x \to 0 lim (\frac{x}{2})

f (x) = e^{x + 1}

x^{\frac{1}{3}} + \frac{x - 4}{3 x ^{\frac{5}{3}}}

What is the sum from k=0 to infinity of (3^k)/(k!) ?
The sum from k=0 to infinity of (3^k)/(k!) is converges