What is the sum from n=1 to infinity of 1/(5^{n+1)} ?

The sum from n=1 to infinity of 1/(5^{n+1)} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of 1/(5^{n+1)}

n = 1 \sum \infty \frac{1}{5 ^{n + 1}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{5 ^{n + 1}}

Apply Series Ratio Test:

converges

= converges

\int 3^{x} + \frac{2}{x} d x

\frac{\partial}{\partial x} (e^{8 x y})

n \to \infty lim (\frac{1}{lo g _{2} ( n )})

\frac{d}{d x} (x^{k})

x \to \infty lim (- \frac{1}{3})

What is the sum from n=1 to infinity of 1/(5^{n+1)} ?
The sum from n=1 to infinity of 1/(5^{n+1)} is converges