What is the derivative of 16e^{-2x} ?

The derivative of 16e^{-2x} is -32e^{-2x}

What is the first derivative of 16e^{-2x} ?

The first derivative of 16e^{-2x} is -32e^{-2x}

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\frac{d}{d x} (16 e^{- 2 x})

- 32 e^{- 2 x}

Solution steps

\frac{d}{d x} (16 e^{- 2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (e^{- 2 x})

Apply the chain rule:

e^{- 2 x} \frac{d}{d x} (- 2 x)

= e^{- 2 x} \frac{d}{d x} (- 2 x)

\frac{d}{d x} (- 2 x) = - 2

= 16 e^{- 2 x} (- 2)

Simplify

= - 32 e^{- 2 x}

n = 3 \sum \infty \frac{3}{2} \cdot \frac{1}{4 ^{n}}

\int_{0}^{8} f (x) d x

\frac{d x}{d t} = \frac{2 t ^{2} + x ^{2}}{t x}

\frac{d ^{2}}{d x ^{2}} (x^{\frac{1}{2}})

\frac{\partial}{\partial s} (arctan (rs))

What is the derivative of 16e^{-2x} ?
The derivative of 16e^{-2x} is -32e^{-2x}
What is the first derivative of 16e^{-2x} ?
The first derivative of 16e^{-2x} is -32e^{-2x}