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Popular >

y^'-4y=e^{-4t}

Solution

y^{^{'}} - 4 y = e^{- 4 t}

Solution

y = - \frac{1}{8 e ^{4 t}} + c_{1} e^{4 t}

Solution steps

y^{'} (t) - 4 y = e^{- 4 t}

Solve linear ODE:

y = - \frac{1}{8 e ^{4 t}} + c_{1} e^{4 t}

y = - \frac{1}{8 e ^{4 t}} + c_{1} e^{4 t}

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Frequently Asked Questions (FAQ)

What is the solution for y^'-4y=e^{-4t} ?
The solution for y^'-4y=e^{-4t} is y=-1/(8e^{4t)}+c_{1}e^{4t}